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y^2-5.2y+1=0
a = 1; b = -5.2; c = +1;
Δ = b2-4ac
Δ = -5.22-4·1·1
Δ = 23.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5.2)-\sqrt{23.04}}{2*1}=\frac{5.2-\sqrt{23.04}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5.2)+\sqrt{23.04}}{2*1}=\frac{5.2+\sqrt{23.04}}{2} $
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